Table of Contents
In order to find the center and radius, we need to change the equation of the circle into standard form, ( x − h ) 2 + ( y − k ) 2 = r 2 (x-h)^2+(y-k)^2=r^2 (x−h)2+(y−k)2=r2, where h and k are the coordinates of the center and r is the radius.
How do we find the radius of a circle?
How to Find the Radius of a Circle? When the diameter is known, the formula for the radius of a circle is: Radius = Diameter / 2. When the circumference is known, the formula for the radius is: Radius = Circumference / 2π When the area is known, the formula for the radius is: Radius = ⎷(Area of the circle / π).
What formula is to be used to solve for the center of a circle given the endpoints of its diameter?
(x−h)2+(y−k)2=r2 ( x – h ) 2 + ( y – k ) 2 = r 2 is the equation form for a circle with r radius and (h,k) as the center point. In this case, r=√26 and the center point is (2,7) . The equation for the circle is (x−(2))2+(y−(7))2=(√26)2 ( x – ( 2 ) ) 2 + ( y – ( 7 ) ) 2 = ( 26 ) 2 .
What is the equation of a circle with center 3/5 and radius 4?
Explanation: A general circle with centre (a,b) and radius r has equation (x−a)2+(y−b)2=r2 .
What is general equation of circle?
The general equation of a circle is. x2+y2+2gx+2fy+c=0.
How do you write the equation of a circle with the center and radius?
The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.
What is the equation of a circle with center (- 2 and radius 3?
The standard form of the equation of a circle is. where (a ,b) are the coordinates of the centre and r, the radius. Substitute these values into the standard equation. ⇒(x+2)2+(y+3)2=9 is the circle’s equation.
What is the equation of a circle with center (- 3/5 and radius?
Answer: The equation of the circle, can be given as (x + 3)2 + (y + 5)2 = 36. Explanation: Given, center coordinates = (-3, -5) and radius = 6 units.
What is the equation of a circle with center 5?
1 Expert Answer The equation of a circle is (x-h)2 + (y-k)2 = r2 where: (h,k) = the coordinates of the circle’s center = (5.
What is an equation of a circle with center − 2 − 1 and radius 3?
The equation of the circle whose center is (2,1) and radius is 3 is (x – 2)2 + (y – 1)2 = 9.
What is the equation of a circle with center (- 3?
The equation of a circle is (x−h)2+(y−k)2=r2 , where (h,k) is the center and r is the radius. If the center is at (−3,0) and the endpoint of the radius is at (3,0) , then the length of the radius is the distance between the two points, which is 3−(−3)=6 .
What is the equation of a circle with center 2?
The equation of a circle with center (h,k) and radius r units is (x−h)2+(y−k)2=r2 .
What is the general equation of the circle that has a center at 2/3 and has a radius of 3 units?
The equation of the circle with center (-2,3) and radius = 3 units will be x2 + y2 + 4x – 6y + 4 = 0.
What is the equation of a circle whose center is 3/5 and whose radius is 2 cm?
The equation of a circle with the center (3,5) and radius = 2 cm is (x – 3)2 + (y – 5)2 = 4.
What is the standard equation of circle with center 3/5 and radius 6?
The general equation for a circle is (x−h)2+(y−k)2=r2 , where (h,k) is the center and r is the radius.
What is the equation of a circle with a center located at (- 3/5 and a radius of 6?
The equation that represents a circle with a center at (-3, -5) and a radius of 6 units is (x + 3)2 + (y + 5)2 = 36.
How do you write the equation of a circle given its radius and its center at the origin What about if the center is at H k )?
The equation of a circle written in the form (x−h)2+(y−k)2=r2 where (h,k) is the center and r is the radius. The circle centered at the origin with radius 1; its equation is x2+y2=1.
What is the equation of a circle with a center at 2/3 and a radius of 4?
The equation of the circle with center (2, -3) and a radius of 4 is x2 + y2 – 4x + 6y = 3.
What is the radius and center of this equation?
The center-radius form is: (x−h)2+(y−k)2=r2 Here, the center point is denoted by (h,k) and r is the radius of the circle.
What is the general equation of the circle with center 4 3 and radius 3?
The equation of the circle with center (−3,−4) and radius 3,in standard form, is: (x+3)2+(y+4)2 = 9.
What is the equation of the circle with a center at the point and a radius of 4 units?
(x – 2)2 + (y + 5)2 = 4. Solution: Given: Center of the circle = (-2 ,5) and radius = 4 units. Where (x, y) is any point on the given circle, (α, β) is the center of the given circle and r is the radius of the given circle.
How do you find the radius of a circle with the circumference?
To find the radius from the circumference of a circle, you have to do the following: Divide the circumference by π, or 3.14 for an estimation. The result is the circle’s diameter. Divide the diameter by 2. There you go, you found the circle’s radius.
What will be the equation of a circle with center at the origin and radius of 5 units?
x2+y2=5.
What is the radius of a circle whose equation is x2 y2 8x − 6y 21 0?
The radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0 is 5units.
Which equation represents a circle with a center at (- 4 9?
Summary: The equation which represents a circle with a center at (-4, 9) and a diameter of 10 units is (x + 4)2 + (y – 9)2 = 25.
Does the point 2 StartRoot 6 EndRoot lie on the circle shown?
Does the point (2,root of 6) lie on the circle shown? Explain. No, the distance from (0, 0) to (2, root of 6) is not 3 units. Does the point (1, StartRoot 7 EndRoot) lie on the circle shown?.
What is the center of a circle whose equation is x2 y2 4x 8y 11 0?
The center of the circle of the given equation is x2 + y2 + 4x – 8y + 11 = 0 is (-2, 4).
Which equation represents a circle with a center at and radius of 6 units?
So, if the center is (0,0) and the radius is 6, an equation of the circle is: (x-0)2 + (y-0)2 = 62.
Which point is on the circle centered at the origin with a radius of 5?
The point on the circle centered at the origin with a radius of 5 units is (2 , √21).
How do you write the equation of a circle given its radius if the center is the origin?
If the center of a circle is (0, 0), then the equation of the circle is of the form x^2+y^2=r^2, where r is the radius. The radius of a circle is the distance from the center of the circle to the edge of the circle.
How do you write the equation of a circle given its radius if the center is not at the origin?
In this lesson, you learned the equation of a circle that is centered somewhere other than the origin is (x−h)2+(y−k)2=r2, where (h,k)is the center.
